2y^2-7y+10=0

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Solution for 2y^2-7y+10=0 equation:


Simplifying
2y2 + -7y + 10 = 0

Reorder the terms:
10 + -7y + 2y2 = 0

Solving
10 + -7y + 2y2 = 0

Solving for variable 'y'.

Begin completing the square.  Divide all terms by
2 the coefficient of the squared term: 

Divide each side by '2'.
5 + -3.5y + y2 = 0

Move the constant term to the right:

Add '-5' to each side of the equation.
5 + -3.5y + -5 + y2 = 0 + -5

Reorder the terms:
5 + -5 + -3.5y + y2 = 0 + -5

Combine like terms: 5 + -5 = 0
0 + -3.5y + y2 = 0 + -5
-3.5y + y2 = 0 + -5

Combine like terms: 0 + -5 = -5
-3.5y + y2 = -5

The y term is -3.5y.  Take half its coefficient (-1.75).
Square it (3.0625) and add it to both sides.

Add '3.0625' to each side of the equation.
-3.5y + 3.0625 + y2 = -5 + 3.0625

Reorder the terms:
3.0625 + -3.5y + y2 = -5 + 3.0625

Combine like terms: -5 + 3.0625 = -1.9375
3.0625 + -3.5y + y2 = -1.9375

Factor a perfect square on the left side:
(y + -1.75)(y + -1.75) = -1.9375

Can't calculate square root of the right side.

The solution to this equation could not be determined.

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